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Density of Cement = 1440 kg/ m 3 = 0.3636 X 1440 = 523 kg = 10.5 Approx. Bags . Sand Quantity = ( Sand Part / Concrete Parts ) * Concrete Volume = (1.5/5.5) * 2 = 0.5454 m 3. Coarse Aggregate = (Coarse Aggregate Part / Concrete Parts ) * Concrete Volume = (3/5.5) * 2 = 1.09 m 3

Learn MoreHow to calculate sand and coarse aggregate?

Learn MoreQuantity of Sand in kg = 0.44 × 1450 (density of sand = 1450 to 1500 kg/m3) Quantity of Sand in cubic feet = 1.54 / 7 × 2 × 35.314 (1 cum = 35.314 cft ) = 15.53 cft. Alternative way . Quantity of Sand in cubic feet = Nos of cement bags x Volume of one bag cement in cft × Ratio of sand = 6.336 × 1.226 × 2

Learn MoreAug 03, 2018 · M-20 = 1 : 1.5 : 3 = 5.5, (Cement : Sand : Aggregate) Some of Mix is – 5.5. Where, M = Mix 20 = Characteristic Compressive strength. Consider volume of concrete = 1m3. Dry Volume of Concrete = 1 x 1.54 = 1.54 m3 (For Dry Volume Multiply By 1.54) Now we start calculation for find Cement, Sand and Aggregate quality in 1 cubic meter concrete

Learn MoreSep 24, 2020 · = 7.89 nos of cement bag required for 1m3 concrete. Quantity of Sand: Quantity of sand =(1.5/5.5) X 1.52 = 0.414m3. Quantity of Coarse aggregate: quantity of coarse aggregate = (3/5.5) X 1.52 = 0.829m3. That means for 1m3, 8 nos of cement bags, 0.414m3 sand, and 0.829m3 aggregate quantity in concrete required for M20 Grade concrete.

Learn MoreMore Calculate Cement Sand Aggregate Quantity videos

Learn MoreConsideration volume of concrete = 1m3. Dry Volume of Concrete = 1 x 1.54 = 1.54 m3 (For Dry Volume Multiply By 1.54) Now that we know these, presently we will start estimating the Cement, Sand and Aggregate quality in 1 cubic meter concrete. Cement. Cement= (1/5.5) x 1.54 = 0.28 m3.

Learn MoreQuantity of Coarse Aggregates =Quantity of cement x 1.5 Quantity of Coarse Aggregates = 0.28 x 3 =0.84 m³ or Quantity of coarse aggregates = (3/5.5)*1.54 = 0.84 m³ 1 m³=35.3147 Cubic Feet (CFT)

Learn MoreSince we know the ratio of cement to sand (1:2) and cement to aggregate (1:4) Volume of Sand required would be = 0.035*2 = 0.07 cubic meter (cum) Volume of Aggregate required would be = 0.035*4 = 0.14 cubic meter (cum)

Learn MoreWet Volume of concrete = Dry Volume of concrete + 55% of dry volume of concrete or. Wet Volume of concrete = Dry Volume of concrete x 1.55. So whatever volume we get from the above formula, we need to multiply the value with 1.55%. Now back to the calculation, Sum of total parts = 1+1.5+3 = 5.5 Parts.

Learn MoreAssuming bulk densities of materials per cubic meter, cubic feet and cubic yards as follows: Cement = 1500 kg/m3 = 93.642 lb/ft3 = 2528.332 lb/cubic yards. Sand = 1700 kg/m3 = 105 lb/ft3 = 2865.443 lb/cubic yards. Coarse aggregates = 1650 kg/m3 = 103 lb/ft3 = 2781.166 lb/cubic yards.

Learn MoreNow from this dry volume we can find out the volume of cement , Sand and aggregate in concrete column. 1- Volume of cement = V = 1/5.5 x dry volume = V = 1/5.5 x 0.4158 = V = 0.0756 m3. Now convert the cment volume to bags. Volume of cement / Volume of one cement bag in m3. Note : Volume of Cement bag = 0.0347

Learn MoreHow To Calculate Cement, Sand And Aggregate Quantity In Concrete November 29, 2016 admin 20 Comments Calculate The Unit Weight of M.S Angle For Billing

Learn MoreNow question is how to calculate cement, sand and aggregate quantity in in m15 concrete, their answer will be as follow:- Ans. :- 6.336 bags (316.8 kgs) of cement, 15.54 cu ft sand and 31 cu ft aggregate quantity are used in m15 grade of 1m3 concrete.

Learn MoreConcrete Material Calculator, Just enter the volume of concrete and it will give the calculated quantity of material like sand, aggregate, and cement.

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